(X+2/x-4)+(1/x+4)=(x^2+2)/(x^2-16)

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Solution for (X+2/x-4)+(1/x+4)=(x^2+2)/(x^2-16) equation: 



(X+2/X-4)+(1/X+4)=(X^2+2)/(X^2-16)

We move all terms to the left:

(X+2/X-4)+(1/X+4)-((X^2+2)/(X^2-16))=0



Domain of the equation: X-4)!=0

X∈R





Domain of the equation: X+4)!=0

X∈R





Domain of the equation: (X^2-16))!=0

X∈R



We get rid of parentheses

X+2/X+1/X-((X^2+2)/(X^2-16))-4+4=0

We calculate fractions

We do not support eXpression: X^3

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